Find Column Name,Text from Tables In A Sql Server Database

Below Stored Procedure is used "To Find Column Name,Text from Tables In A Sql Server Database" : Just copy Paste the below query in query window of Sql Server Database, execute it and then pass the text , execute it the search result will shown :

Create PROC [dbo].[SearchAllTables]

(

@SearchStr nvarchar(100)

)

AS

BEGIN

    CREATE TABLE #Results (ColumnName nvarchar(370), ColumnValue nvarchar(3630))

    SET NOCOUNT ON

    DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)

    SET  @TableName = ''

    SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')

    WHILE @TableName IS NOT NULL

    BEGIN

        SET @ColumnName = ''

        SET @TableName =

        (

            SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))

            FROM     INFORMATION_SCHEMA.TABLES

            WHERE         TABLE_TYPE = 'BASE TABLE'

                AND    QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName

                AND    OBJECTPROPERTY(

                        OBJECT_ID(

                            QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)

                             ), 'IsMSShipped'

                               ) = 0

        )

        WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)

        BEGIN

            SET @ColumnName =

            (

                SELECT MIN(QUOTENAME(COLUMN_NAME))

                FROM     INFORMATION_SCHEMA.COLUMNS

                WHERE         TABLE_SCHEMA    = PARSENAME(@TableName, 2)

                    AND    TABLE_NAME    = PARSENAME(@TableName, 1)

                    AND    DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar', 'int', 'decimal')

                    AND    QUOTENAME(COLUMN_NAME) > @ColumnName

            )

            IF @ColumnName IS NOT NULL

            BEGIN

                INSERT INTO #Results

                EXEC

                (

                    'SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630)

                    FROM ' + @TableName + 'WITH (NOLOCK) ' +

                    ' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2

                )

            END

        END   

    END

    SELECT ColumnName, ColumnValue FROM #Results

END